4.9x-16x^2+12=0

Solution for 4.9x-16x^2+12=0 equation:

4.9x-16x^2+12=0

a = -16; b = 4.9; c = +12;
Δ = b2-4ac
Δ = 4.92-4·(-16)·12
Δ = 792.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.9)-\sqrt{792.01}}{2*-16}=\frac{-4.9-\sqrt{792.01}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.9)+\sqrt{792.01}}{2*-16}=\frac{-4.9+\sqrt{792.01}}{-32}
$